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7s^2-13s-24=0
a = 7; b = -13; c = -24;
Δ = b2-4ac
Δ = -132-4·7·(-24)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-29}{2*7}=\frac{-16}{14} =-1+1/7 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+29}{2*7}=\frac{42}{14} =3 $
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